Post №200
by ACJTest MathJax + MarkDown.
\[ x = {-b \pm \sqrt{b^2-4ac} \over 2a} \]
Alexander Christiaan Jacob Dekker
Posts
Post №199
by ACJ
Test _MathJax_ + _MarkDown_.
\\[ x = {-b \pm \sqrt{b^2-4ac} \over 2a} \\]
\\[ x = {-b \pm \sqrt{b^2-4ac} \over 2a} \\]
Post №198
by ACJ
Test _MathJax_ + _MarkDown_.
\\[ x = {-b \pm \sqrt{b^2-4ac} \over 2a} \\]
\\[ x = {-b \pm \sqrt{b^2-4ac} \over 2a} \\]
Post №197
by ACJ
Test _MathJax_ + _MarkDown_.
\\[ x = {-b \pm \sqrt{b^2-4ac} \over 2a} \\]
\\[ x = {-b \pm \sqrt{b^2-4ac} \over 2a} \\]
Post №47
by ACJ
You can now edit and delete your own posts. I think Kim K would approve.
Post №42
by ACJ
Testing post with \(\rm\LaTeX\) from new dashboard.
Post №36
by ACJ
Testing some \(\rm\TeX\) markup:
$$W = \int_{k\lt\Lambda}[Dg][DA][D\psi][D\Phi]\exp\left\{i\int{d^4x\sqrt{-g}\left[\frac{m^2_p}{2}R\\-\frac{1}{4}F^a_{\mu \nu}F^{a\mu\nu}+i\bar\psi^i\gamma^\mu D_\mu\psi^i+\left(\bar\psi^i_L V_{ij}\Phi\psi^j_R+\text{h.c.}\right)-|D_\mu\Phi|^2-V(\Phi)\right]}\right\}$$
$$W = \int_{k\lt\Lambda}[Dg][DA][D\psi][D\Phi]\exp\left\{i\int{d^4x\sqrt{-g}\left[\frac{m^2_p}{2}R\\-\frac{1}{4}F^a_{\mu \nu}F^{a\mu\nu}+i\bar\psi^i\gamma^\mu D_\mu\psi^i+\left(\bar\psi^i_L V_{ij}\Phi\psi^j_R+\text{h.c.}\right)-|D_\mu\Phi|^2-V(\Phi)\right]}\right\}$$
Comments
Comment №1
by ACJComment test.
$$e^{i\pi}+1=0$$
Post №13
by ACJ
Working on Your Mimesia Contacts.
Post №12
by ACJ
Lekkerseg…
Post №11
by ACJ
Yay!
Post №10
by ACJ
Testing…
Comments